Answering Service for Software Development, Masters in Mathematics ,Virus Protection and Design.: 11/24/12

Actually, the easiest way is to use one of the many factoring calculators you find on the internet. Just Google on "factoring calculator," and you'll find a raft of them, mostly free. Try a few. Pick one you like.

But, if you MUST be traditional, here are some clues for solving this by "inspection." That is a great term. It means keep guessing until you get it.

Here, you see the plus six on the end. The only way to get a plus there is to have the signs alike in the two binomials. They must either be both pluses, or both minuses.

Then you see there are a couple minus terms in what you are trying to factor, That means there is at least one minus sign somewhere. And you know already the signs are alike. So,that proves that the signs in BOTH your binomials will be negative, because you couldn't get a negative in the product AND a positive final number any other way.

So far, you have in your mental picture something like this:

(aaa - bbb) * (ccc - ddd)

Now, bbb times ddd must equal 6. Don't waste time with 1 and 6, because the 3 in front of the x tells you 6 would be impossible; it must be 3, and aaa must be -x in order to make the positive 3x in the expression you're factoring. So, keeping up with your absolutely brilliant logic:

(-x - 2) * (ccc - 3)

It's downhill from here. ccc must be some number of y's that make -8y when multiplied by -2. Duhhhh... Let's try 4y. Bingo! It works.

Checking it out:

(-x - 2) * (4y - 3) = 3x -8y -4xy +6

Okay, go make popcorn.

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Open Question: Algebra question: Method explaining?

There are two distinct methods to factoring 64 - x^2:

Method #1:

Use difference of perfect squares.

Method #2:

Factor out -1 and then use the difference of perfect squares.

Both methods are correct. Choose one of the methods and factor the expression. In complete sentences explain why you chose the method that you did and include the final factored form of the expression in your explanation.

Can someone please explain what's going on in this question and provide an answer.

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Open Question: Areas of Shapes? Maths homework please help?

A square with a perimeter of 16cm calculate the area

Each shape had a area of 40 cm
calculate the height of the parallelogram if the base is 4cm
Calulate the length if the base of the triangle if the height is 4cm
what might be the values of h,a,and b in the trapezium

Smallest to largest
the size length of this square a is 64 cm
the area of this square b is 64 cm2
the perimeter of this square c is 64 cm

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Open Question: Easy algebra fractions?

1/x+7 + 1/x+4 =

1/x+6 - 1/x+7

5/x+6 + 4/x+4

Sorry, I could not read the content fromt this page.

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Open Question: anyone please answer this for me dy/dt=ky ln 200/y?

dy/dt = k * y * ln(200 / y)
dy / (y * ln(200 / y)) = k * dt
dy / (y * (ln(200) - ln(y))) = k * dt

u = ln(200) - ln(y))
du = -dy / y

-du / u = k * dt

Integrate

-ln|u| = kt + C
ln|u| = -(kt + C)
u = e^(-kt + C)
ln(200 / y) = e^(-(kt + C))

ln(200 / 20) = e^(-C)
ln(10) = e^(-C)
1 / ln(10) = e^(C)
-ln(ln(10)) = C

ln(200 / y) = e^(-(kt - ln(ln(10))))
ln(200 / y) = e^(ln(ln(10)) - kt)
ln(200 / y) = ln(10) * e^(-kt)

ln(200 / 48) = ln(10) * e^(-3k)
ln(25/6) = ln(10) * e^(-3k)
e^(3k) = ln(10) / ln(25/6)
3k = ln(ln(10) / ln(25/6))
k = (1/3) * ln(ln(10) / ln(25/6))

ln(200 / y) = ln(10) * e^((-1/3) * ln(ln(10) / ln(25/6)) * t)
ln(200 / y) = ln(10) * (ln(10) / ln(25/6)) * e^(-t/3)
ln(200 / y) = ln(10)^2 * e^(-t/3) / ln(25/6)

t = 15

ln(200 / y) = ln(10)^2 * e^(-5) / ln(25/6)
200 / y = e^(ln(10)^2 * e^(-5) / ln(25/6))
y / 200 = 1 / e^(ln(10) * ln(10) * e^(-5) / ln(25/6))
y = 200 / e^(ln(10)^2 / (e^(5) * ln(25/6)))
y = 195.05569516562951956450191705787

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