How do you work this out? PLEASE HELP!
Thanks in advance :)
Open Question: Complex question about tangents/normals of a graph?
Find the equations of the tangent and the normal to the graph with equation y = (1/x) - (4/x^2) at the points where x = 1 and x = 8.
Open Question: A baseball player's batting average is .254 (254 hits per 1000 at bats).?
3 times 52 is 156 at bats. Multiply that by .254 and you'll have your answer.
I'll let you take it from here.
Open Question: Describe the steps you would use to solve this problem.?
40mm = 8m
32mm = 6.4m
8 X 6.4 = 51.2 m^2
1 m = 1.09361 yards
1 sqm = 1.09361 X 1.09361 sq yards
1.09361 X 1.09361 X 10.89 = 13.02 $
ANSWER
Open Question: Can someone please help me factorize this problem?
ANSWER:
(-x - 2) * (4y - 3) = 3x -8y -4xy +6
(-x - 2) * (4y - 3) = 3x -8y -4xy +6
But HOW do you get it?
Actually, the easiest way is to use one of the many factoring calculators you find on the internet. Just Google on "factoring calculator," and you'll find a raft of them, mostly free. Try a few. Pick one you like.
But, if you MUST be traditional, here are some clues for solving this by "inspection." That is a great term. It means keep guessing until you get it.
Here, you see the plus six on the end. The only way to get a plus there is to have the signs alike in the two binomials. They must either be both pluses, or both minuses.
Then you see there are a couple minus terms in what you are trying to factor, That means there is at least one minus sign somewhere. And you know already the signs are alike. So,that proves that the signs in BOTH your binomials will be negative, because you couldn't get a negative in the product AND a positive final number any other way.
So far, you have in your mental picture something like this:
(aaa - bbb) * (ccc - ddd)
Now, bbb times ddd must equal 6. Don't waste time with 1 and 6, because the 3 in front of the x tells you 6 would be impossible; it must be 3, and aaa must be -x in order to make the positive 3x in the expression you're factoring. So, keeping up with your absolutely brilliant logic:
(-x - 2) * (ccc - 3)
It's downhill from here. ccc must be some number of y's that make -8y when multiplied by -2. Duhhhh... Let's try 4y. Bingo! It works.
Checking it out:
(-x - 2) * (4y - 3) = 3x -8y -4xy +6
Okay, go make popcorn.
Open Question: Algebra question: Method explaining?
There are two distinct methods to factoring 64 - x^2:
Method #1:
Use difference of perfect squares.
Method #2:
Factor out -1 and then use the difference of perfect squares.
Both methods are correct. Choose one of the methods and factor the expression. In complete sentences explain why you chose the method that you did and include the final factored form of the expression in your explanation.
Can someone please explain what's going on in this question and provide an answer.
Open Question: Areas of Shapes? Maths homework please help?
A square with a perimeter of 16cm calculate the area
Each shape had a area of 40 cm
calculate the height of the parallelogram if the base is 4cm
Calulate the length if the base of the triangle if the height is 4cm
what might be the values of h,a,and b in the trapezium
Smallest to largest
the size length of this square a is 64 cm
the area of this square b is 64 cm2
the perimeter of this square c is 64 cm
Open Question: Easy algebra fractions?
1/x+7 + 1/x+4 =
1/x+6 - 1/x+7
5/x+6 + 4/x+4
Sorry, I could not read the content fromt this page.Open Question: anyone please answer this for me dy/dt=ky ln 200/y?
dy/dt = k * y * ln(200 / y)
dy / (y * ln(200 / y)) = k * dt
dy / (y * (ln(200) - ln(y))) = k * dt
dy / (y * ln(200 / y)) = k * dt
dy / (y * (ln(200) - ln(y))) = k * dt
u = ln(200) - ln(y))
du = -dy / y
-du / u = k * dt
Integrate
-ln|u| = kt + C
ln|u| = -(kt + C)
u = e^(-kt + C)
ln(200 / y) = e^(-(kt + C))
ln(200 / 20) = e^(-C)
ln(10) = e^(-C)
1 / ln(10) = e^(C)
-ln(ln(10)) = C
ln(200 / y) = e^(-(kt - ln(ln(10))))
ln(200 / y) = e^(ln(ln(10)) - kt)
ln(200 / y) = ln(10) * e^(-kt)
ln(200 / 48) = ln(10) * e^(-3k)
ln(25/6) = ln(10) * e^(-3k)
e^(3k) = ln(10) / ln(25/6)
3k = ln(ln(10) / ln(25/6))
k = (1/3) * ln(ln(10) / ln(25/6))
ln(200 / y) = ln(10) * e^((-1/3) * ln(ln(10) / ln(25/6)) * t)
ln(200 / y) = ln(10) * (ln(10) / ln(25/6)) * e^(-t/3)
ln(200 / y) = ln(10)^2 * e^(-t/3) / ln(25/6)
t = 15
ln(200 / y) = ln(10)^2 * e^(-5) / ln(25/6)
200 / y = e^(ln(10)^2 * e^(-5) / ln(25/6))
y / 200 = 1 / e^(ln(10) * ln(10) * e^(-5) / ln(25/6))
y = 200 / e^(ln(10)^2 / (e^(5) * ln(25/6)))
y = 195.05569516562951956450191705787
Open Question: How to use Riemann sums for this expression?
Let f(x)= 2 + x^3 , 1 less then or equal to x less than or equal to 4. Use the idea of Riemann sums to find an expression for the area under the graph of f as a limit. You do not need to evaluate the limit.
Find the 3rd and 6th approximations of the sum in part a.
Please help. I cannot figure this out.
Open Question: Let F(x) = ʃ t-3 / t^2+7 dt (from 0 to x) for -oo <x<oo?
I assume you mean F(x) = ? (t-3) / (t^2+7) dt (t = 0 to x) ---> don't forget parentheses
F'(x) = (x-3) / (x^2+7)
F''(x) = (1*(x^2+7) - (x-3)(2x)) / (x^2+7)^2
F''(x) = (-x^2+6x+7) / (x^2+7)^2
F''(x) = -(x+1)(x-7) / (x^2+7)^2
a)
F has minimum value where F'(x) = 0 and F''(x) > 0
F'(x) = 0
(x-3) / (x^2+7) = 0
x = 3
F''(3) = -(3+1)(3-7) / (3^2+7)^2 = 16/16^2 = 1/16 > 0
Minimum value at x = 3
b)
F is increasing when F'(x) > 0
(x-3) / (x^2+7) > 0
x - 3 > 0 . . . . . . since (x^2+7) > 0 for all x
x > 3
F is decreasing when F'(x) < 0
x < 3
Increasing on interval (3, 8)
Decreasing on interval (-8, 3)
c)
F is concave up when F''(x) > 0
-(x+1)(x-7) / (x^2+7)^2 > 0
-(x+1)(x-7) > 0 . . . . . . since (x^2+7) > 0 for all x
-1 < x < 7
F is concave down when F''(x) < 0
x < -1 or x > 7
Concave up on interval (-1, 7)
Concave down on intervals (-8, -1) U (7, 8)
Open Question: Integral Problem! 10 Points Go!?
I've got: Integral from pi/4 to Infinity of (4+cos (4x))/(x^3)dx
This is an example of Convergence, but I don't know how to solve it. Any help, even some kind of basic outline is appreciated. Better yet, if you can lead me through all the steps, that would help out a lot. Thanks SO much!
Open Question: MATHS QUESTION PLEASEEEE HELPPP ME!! IM BEGGING!!?
It is noticed that the height of a cone is twice its radius and that the cones volume is exactly 1000cm63. Calculate the dimensions of the cone correct to one decimal place.
please explain your answer thankyou
Open Question: Newton's Second and Third Law Derivations?
Start with Newton's laws F = ma and F_12 = F_21
Show that if two bodies exert a force on each other, ?p_1 = -?p_2
Show that if two bodies exert a force on each other, ?p_1 = -?p_2
How do I do this?
Also, I think I need to somehow derive the following equation from those:
?P = (m_A * v_fA + m_B * v_fB) - (m_A * v_iA + m_B * v_iB)
Where:
m_A = mass of cart A
m_B = mass of cart B
v_fA = final velocity of cart A
v_fB = final velocity of cart B
v_iA = initial velocity of cart A
v_iB = initial velocity of cart B
Context: This is for a physics lab report due today. In the lab we took two carts (A and B) and pushed them into each other and gathered the initial and final velocities of both carts. We are trying to determine whether or not momentum is conserved.
Any help you could provide will be greatly appreciated. Also if you have any tips for writing this lab report, please include those. Thank you so much!
Open Question: Please help math urgent.?
interval notation is simple:
use round brackets for infinity and point that are not included (strictly greater or smaller)
use square bracket for points that are included (greater than or equal, less than or equal)
combine multiple intervals using union
use round brackets for infinity and point that are not included (strictly greater or smaller)
use square bracket for points that are included (greater than or equal, less than or equal)
combine multiple intervals using union
x = -2 and x < 4
since -2 is included, and 4 is not we get
[-2,4)
x < -2 or x = 3
here -2 is not included but 3 is
(-infinity, -2)U[3,infinity)
-4 < a + 2 < 10
this is two inequalities, each should be solved separately
first we have:
-4
a+2>-4
a>-4-2
a>-6
then we also have
a+2<10
a<10-2
a<8
so solution is
(-6,8)
because both -6 and 8 are not included.
last one is
x>=3
x>=6
to satisfy both, we use x>=6
which is
[6,infinity)
note that 6 was included (square bracket)
Open Question: What is the formula to find center coordinates of a square?
let's say the vertex is A(0, 0)
and the length of side is 4
and the length of side is 4
other points would be
B(4, 0)
C(4, 4)
D(0, 4)
the diagnonals are
BD: (4, 0) (0, 4)
and
AC: (0, 0) (4, 4)
midpoint of BD (E)
xE = (4 + 0) / 2
xE = 2
yE = (0 + 4) / 2
yE = 2
E(2, 2)
Midpoint of AC (E)
also equals
E(2, 2)
Open Question: Potential zeros of polynomials?
Determine the maximum numbers of real zeros each polynomial can have. Then list the potential zeros.
1. 6x^4-x^2+2
2. -6x^3-x^2+x+10
Thanks!
Open Question: Visual angle and image size on the retina?
Please tell me the formulas to figure out the answers for each of the problems so that I know how to do them:
Suppose that the focal length of the eye (the distance from the lens to the retina) is 2 cm. Your blind spot subtends an angle of roughly 5 deg. How big is the blind spot (in cm) on your retina? (Use the focal length as the distance in the visual angle equation).
The fovea is roughly 2 deg of visual angle. What is the diameter of the fovea in cm? (Use 2 cm again as the focal length).
Open Question: use given zero to find the remaining zeros of the polynomial?
use given zero to find the remaining zeros of the polynomial?
g(x) = x^3 + 3x^2 + 25x + 75 Zero: -5i
if one zero is (- 5i), then (5i) is also a zero
(x + 5i)(x - 5i) = x^2 + 25
long division by (x^2 + 25) yields the quotient: (x + 3)
the remaining zero is: x = - 3
check
one problem at a time.
@ƒ
Open Question: Where does h'(x) = 0.14 ?
Consider the graphs below. Both functions have a sharp corner at x=50.
m(x)
https://instruct.math.lsa.umich.edu/webwork2_course_files/ma115-042-f12/tmp/gif/kostakoe-3736-sethomework19prob12image1.png
n(x)
https://instruct.math.lsa.umich.edu/webwork2_course_files/ma115-042-f12/tmp/gif/kostakoe-3736-sethomework19prob12image2.png
Let h(x)=n(m(x)). Find a point x where h'(x)=0.14
x = ????
Open Question: What coordinates satisfy this slope?
Technically, your question doesn't make any sense, since a coordinate cannot have a slope, only a line can.
The formula 'y=mx+b' describes a straight line, where 'm' is the slope, and 'b' is the y-intercept.
Any two lines with the same slope will be parallel to each other, so any line whose 'y=mx+b' formula has the same 'm' value and a different 'b' value will satisfy the requirements of your questions.
So, for instance:
y = 10x + 1 and y = 10x + 2 are the formulas for two parallel lines with a slope of 10.
To get coordinates on these lines, just plug in values for 'x' and solve for 'y'. For instance:
(0,1), (1,11), and (2,21) are on the line 'y = 10x + 1', and
(0,2), (1,12), and (2,22) are on the line 'y = 10x + 2'.
(:-o)
Open Question: What data ranges can I create for this data, pic included?
http://www.flickr.com/photos/89180248@N07/8122574897/in/photostream
That's how my spread sheet in excel 2010 looks like and I need to create 7 data ranges for the column that says average dollar amount of each scholarship
Open Question: Simple Ratio question help?
2/5 = x/45
5x = 90
x = 18 ANSWER
Sorry, I could not read the content fromt this page.Open Question: Volume of a cone. please help me!!!?
It is noticed that the height of a cone is twice its radius and that the cones volume is exactly 1000cm63. Calculate the dimensions of the cone correct to one decimal place.
please explain your answer thankyou
Subscribe to:
Posts (Atom)