Calculate the pH of a 0.10 M solution of hypochlorous acid, HOCl .?

Ka of HOCl is 3.5 x 10 ^-8

pH = ?

Original Post

1 comment:

  1. Calculate the [H+] from the Ka equation:
    Ka = [H+]² / [acid]
    3.5*10^-8 = [H+]² / 0.10
    [H+]² = (3.5*10^-8)*0.1
    [H+]² = 3.5*10^-9
    [H+] = 5.92*10^-5

    pH = -log [H+]
    pH =- -log 5.92*10^-5
    pH = 4.23

    ReplyDelete